Dc Pandey Physics Class 11 Pdf Download Part 1 Work Official

Solving for $s$, we get:

An object of mass 2 kg is moving with a velocity of 4 m/s. A force of 5 N is applied in the opposite direction of motion, causing it to slow down. Calculate the work done by the force.

Using the formula $W = F \cdot s$, we get: dc pandey physics class 11 pdf download part 1 work

Now, we can calculate the work done:

$$W = \Delta KE$$

$$v^2 = u^2 + 2as$$

$$s = \frac{u^2}{2a} = \frac{4^2}{2 \cdot \frac{5}{2}} = \frac{16}{5} m$$ Solving for $s$, we get: An object of

$$W = 10 \cdot 5 = 50 J$$